Bill Chun Wai Hung
Lab 7 Prelab
Q1)
Input 1 |
Input 2 |
AND gate Output |
LED Output |
0 |
0 |
0 |
1 |
0 |
1 |
0 |
0 |
1 |
0 |
0 |
0 |
1 |
1 |
1 |
0 |
Q2)
V1=V(0)=5V
V2=0V
I = 20mA
R=170 ohm
Q3)
Yes, the current changes. The resistance of the diode and Rs are in parallel, so the resistance is halved, while the R remains constant.
Q4)
Vin = A sin(wt)
Vc2=Vc3=A/2
In figure 3, at the point of the cursor, Vc2=Vc3=7.5V. The Amplitude of the input voltage is about 15V. The Vc2 and Vc3 are half the value of the input Vin.