EE40 HW5 Numerical Answers:

10.11:
0.5321 mA, 1.369mA

10.13:
582 mV, 564 mV

10.16:
ix = 1.28 mA
vx = 2.17 mV

10.33:
(a) I = 0 A, V = 10 V
(b) I = 6 mA, V = 6 V
(c) I = 33.6 mA, V = 30 V

10.34:
(a) I = 0 A, V = 7.5 V
(b) for Vin = 0 V -> I = 0 A, V = 0 V
    for Vin = 2 V -> I = 2 mA, V = 2 V
    for Vin = 6 V -> I = 5 mA, V = 5 V
    for Vin = 10 V -> I = 5 mA, V = 5 V
(c) HINT: Try different combos of on/off and see what Vins they work for.
    The plot is piecewise linear, and there are only a few possible states.

E2.4:
(b) 5E16 cm^-3
(c) 2E3 cm^-3

E2.10:
(a) 3E5 cm/s
(b) 4.8E4 A/cm^2
(c) 333.3 ps
(d) 666.7

E2.11:
(b) 8.421E3 V/cm
(c) 128 A/cm^2

P2.2:
no = 2E15 cm^-3
po = 5E4 cm^-3

P2.5:
(b) ~345 K

P2.7:
(a) 833.3 V/cm
(b) 1.987 ns
(c) 0.2891%
(d) 124.6 ohms

P2.10:
(b) 6.4 uA
(c) 7.415 V

Problem 1:
(e) 22.13 pF/cm

Problem 2:
(a) n-region: no = 1E17
    p-region: po = 1E16
(b) 227.3 ohms/square
(d) 2.78 V

Problem 3:
(a) n-region: no = 1E17
    p-region: po = 1E16
    p+-region: po = 1.01E18
(b) 412.5 ohms/square
(c) 21.73 ohms/square
(d) 21.52 ohms/square

Problem 4:
(b) Vth = 2 V, Req = 4.5 kohms
(c) V = 1.65 V, I = 0.08 mA (approx)

Problem 6:
(a) 910.6 mV